Get only the first records with deno kv but reversed ordered

I'm using Deno KV to store articles.

Generating the ID for the articles:

export function generateUniqueChronologicallyOrderedId(): string {
  return ulid();
}

export function generateUniqueChronologicallyOrderedId(): string {
  return ulid();
}

export function generateUniqueChronologicallyOrderedId(): string {
  return ulid();
}

export function generateUniqueChronologicallyOrderedId(): string {
  return ulid();
}

this will order the articles in the DB chronologically in an ascendent way.

If I want to get all the articles reversed ordered I'm doing:

export async function getAllArticles() {
  const articles = [];

  for await (const res of kv.list({ prefix: ["article"] })) {
    articles.push(res.value);
  }

  return articles.reverse();
}

export async function getAllArticles() {
  const articles = [];

  for await (const res of kv.list({ prefix: ["article"] })) {
    articles.push(res.value);
  }

  return articles.reverse();
}

export async function getAllArticles() {
  const articles = [];

  for await (const res of kv.list({ prefix: ["article"] })) {
    articles.push(res.value);
  }

  return articles.reverse();
}

export async function getAllArticles() {
  const articles = [];

  for await (const res of kv.list({ prefix: ["article"] })) {
    articles.push(res.value);
  }

  return articles.reverse();
}

But I want to get only the 4 most recent articles.
How can I achieve that without waiting for the full database to load and then reverse it?

Thank you very much for your help community!

Get only the first records with deno kv but reversed ordered

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