Type alias with inherited type parameter constraints

Is there any way to do this? I want SVLTN to just be a short-name alias for SomeVeryLongTypeName, and I want it to have the same parameter types, but I don't want to have to specify all of them explicitly.

type SomeVeryLongTypeName<A extends ..., B extends ..., ...> = ...
type SVLTN<A extends ..., B extends ..., ...> = SomeVeryLongTypeName<A, B, ...>

type SomeVeryLongTypeName<A extends ..., B extends ..., ...> = ...
type SVLTN<A extends ..., B extends ..., ...> = SomeVeryLongTypeName<A, B, ...>

What I would like more is:

type SVLTN = SomeVeryLongTypeName<???>

type SVLTN = SomeVeryLongTypeName<???>

Anyone?

Deno•3y ago•

8 replies

abi

Type alias with inherited type parameter constraints

type SomeVeryLongTypeName<A extends ..., B extends ..., ...> = ...
type SVLTN<A extends ..., B extends ..., ...> = SomeVeryLongTypeName<A, B, ...>

type SomeVeryLongTypeName<A extends ..., B extends ..., ...> = ...
type SVLTN<A extends ..., B extends ..., ...> = SomeVeryLongTypeName<A, B, ...>

What I would like more is:

type SVLTN = SomeVeryLongTypeName<???>

type SVLTN = SomeVeryLongTypeName<???>

Anyone?

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Type alias with inherited type parameter constraints

Type alias with inherited type parameter constraints

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